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WebGraphing.com Forum » List all forums » » Forum: Precalculus and Trigonometry Homework Help » » » Thread: Resultants and force |
| Posted by mdetaos at Nov 17, 2006 3:02:07 PM |
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Resultants and force Have worked the following problem but am uncomfortable with the answer and not at all confident with working in this area. Could I please ask if this is the right answer and way to approach it? Thanks! Find the force required to keep a 17,900 pound truck parked on a hill that makes an angle of 4 degrees 20 seconds with the horizontal. (my answer: 236903.2449) Seems too large... First I converted the angle to 4.3333. I know one angle is 90 degrees so the remaining angle must be 85.667. I then set up the equation sin4.3333=17900/x and solved for x. I have a feeling I've missed a step or something... Thanks for your help! |
| Posted by pskinner at Nov 18, 2006 11:54:52 PM |
Re: Resultants and forceI like your metacognitive approach. Any answer that requires more force than the weight of the truck, 17,900 pounds, seems incorrect. The reverse of your ratio has more credibility: x/17900=sin(4.33) In fact, this ratio has the virtue of yielding 0 if instead of 4.33 degrees it were 0 degrees, where no force would be required. ---------------------------------------- Principal Skinner |
| Posted by mdetaos at Nov 19, 2006 7:58:33 AM |
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Re: Resultants and force Thank you. I discovered that I haad made a error in imput which gave me that huge answer. Help much appreciated! |