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WebGraphing.com Forum » List all forums » Forum: Precalculus and Trigonometry Homework Help » Thread: Resultants and force |
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Total posts in this thread: 3 |
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mdetaos
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Have worked the following problem but am uncomfortable with the answer and not at all confident with working in this area. Could I please ask if this is the right answer and way to approach it? Thanks! Find the force required to keep a 17,900 pound truck parked on a hill that makes an angle of 4 degrees 20 seconds with the horizontal. (my answer: 236903.2449) Seems too large... First I converted the angle to 4.3333. I know one angle is 90 degrees so the remaining angle must be 85.667. I then set up the equation sin4.3333=17900/x and solved for x. I have a feeling I've missed a step or something... Thanks for your help! |
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pskinner
Joined: Apr 2, 2005 Posts: 797 Status: Offline |
I like your metacognitive approach. Any answer that requires more force than the weight of the truck, 17,900 pounds, seems incorrect. The reverse of your ratio has more credibility: x/17900=sin(4.33) In fact, this ratio has the virtue of yielding 0 if instead of 4.33 degrees it were 0 degrees, where no force would be required. ---------------------------------------- Principal Skinner |
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mdetaos
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Thank you. I discovered that I haad made a error in imput which gave me that huge answer. Help much appreciated! |
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Re: Resultants and force