WebGraphing.com Homepage Welcome Guest   | Login   
  Search  
  Index  | Recent Threads  | Who's Online  | Register  | Search  | Help  | RSS feeds



Quick Go »
Thread Status: Normal
Total posts in this thread: 3
[Add To My Favorites] [Watch this Thread] [Post new Thread]
Author
Previous Thread This topic has been viewed 15280 times and has 2 replies Next Thread
Female 0414607


us
Joined: Mar 11, 2007
Posts: 5
Status: Offline

f(x)=log2(x+3) Reply to this Post
Reply with Quote

Thank you for your help on my last question.
How do I write f(x)=log2(x+3) in the graphing calculator?

Thanks again.
[Apr 3, 2007 3:29:28 PM] Show Post Printable Version     [Link] Report threaten post: please login first  Go to top 
Female 0414607


us
Joined: Mar 11, 2007
Posts: 5
Status: Offline

Re: f(x)=log2(x+3) Reply to this Post
Reply with Quote

Actually, I figured it out. It's y=log(x+3)/log(2)
[Apr 3, 2007 3:58:48 PM] Show Post Printable Version     [Link] Report threaten post: please login first  Go to top 
Female pskinner

Member's Avatar


Joined: Apr 2, 2005
Posts: 797
Status: Offline
smile   Re: f(x)=log2(x+3) Reply to this Post
Reply with Quote

I gather that you are looking to plot the logarithm to the base 2 of the expression (x+3). An alternative to your way of entering the function is to enter it here as:

log(2,x+3)

This is the alternative notation to express the logarithm to the base 2 of (x+3).
----------------------------------------
Principal Skinner
[Apr 3, 2007 7:36:54 PM] Show Post Printable Version     [Link] Report threaten post: please login first  Go to top 
[Show Thread Printable Version] [Post new Thread]