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4237183

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Joined: Mar 1, 2007
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GROUNDHOG DAY

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It's me AGAIN! Could you please help!?

In2 + In(x-6)=In(x+2)

I was okay until they threw in In2

Thanks very much AGAIN!

[Apr 12, 2007 6:43:08 PM]

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pskinner

Joined: Apr 2, 2005
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Re: GROUNDHOG DAY

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It's me AGAIN! Could you please help!?

In2 + In(x-6)=In(x+2)

I was okay until they threw in In2

Thanks very much AGAIN!

Well, ln(2)+ln(x-6)=ln[2(x-6)]. (That's a key property of logs.) So, from

ln[2(x-6)]=ln(x+2)

since ln is a 1-1 function, you can set the arguments equal:

2(x-6)=x+2

with the proviso that each side must be positive (since ln is only defined on positive numbers).

2x-12=x+2 implies that x=14 and this value is ok for the original equation.
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Principal Skinner

[Apr 12, 2007 9:11:40 PM]

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