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WebGraphing.com Forum » List all forums » Forum: Precalculus and Trigonometry Homework Help » Thread: inequality problem |
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Total posts in this thread: 2 |
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caizza5
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x^2<3x+4 I just dont know how to solve this |
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pskinner
Joined: Apr 2, 2005 Posts: 797 Status: Offline |
Add -(3x+4) to both sides and get: x^2-3x-4<0 Factor the left side: (x-4)(x+1)<0 Now, the left side changes signs only at two points: x=4 and x=-1. Make up a sign chart: -infinity to -1, -1 to 4, and 4 to infinity. Take test values on each interval, say x=-2, x=0, and x=5 for example. That will tell you on which interval or intervals the left side value is negative. Hope this helps! ---------------------------------------- Principal Skinner |
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Re: inequality problem