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WebGraphing.com Forum » List all forums » Forum: Precalculus and Trigonometry Homework Help » Thread: Rewriting an Expression in the form a+bi |
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Total posts in this thread: 2 |
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USA Joined: Jul 6, 2007 Posts: 36 Status: Offline |
I have this problem: If we rewrite the expression 1/1-i - 1/i in the form a+bi (i^2=-1), the result will be... The furthest I have gotten in solving this is 1/2-1/i But the book says the answer is: 1/2+3/2i I'm brand new to this, so what am I doing wrong? |
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Joined: Apr 2, 2005 Posts: 694 Status: Offline |
The technique is to "rationalize the denominator" by multiplying by the conjugate: 1/(1-i)=1*(1+i)/[(1-i)(1+i)]=(1+i)/[1-i^2]=(1+i)/[1+1)=(1/2)(1+i)=1/2+(1/2)i As for the second fraction: -1/i=-1*i/(i*i)=-i/[i^2]=-i/(-1)=i Now, you can add the two fractions to get the book answer. ---------------------------------------- Principal Skinner |
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