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Female EternalSummer247

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Finding an equation... Reply to this Post
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I'm doing a chapter one test in Precalculus Demystified and one of the questions is...

Find an equation of the line containing the point (-1, -5) and parallel to the line y=2x-4

Through the book up until this point, the book does not cover how to solve a problem that's written like this. I've tried working the problem in other ways, but I've come up with nothing because I don't have any x2 and y2 values.

How do I solve this?

Thanks
[Jan 13, 2009 7:18:47 PM] Show Post Printable Version        http://www.myspace.com/psnerd [Link] Report threaten post: please login first  Go to top 
Female pskinner

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applause   Re: Finding an equation... Reply to this Post
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I'm doing a chapter one test in Precalculus Demystified and one of the questions is...

Find an equation of the line containing the point (-1, -5) and parallel to the line y=2x-4

Through the book up until this point, the book does not cover how to solve a problem that's written like this. I've tried working the problem in other ways, but I've come up with nothing because I don't have any x2 and y2 values.

How do I solve this?

Thanks


y=mx+b is the equation of a line with slope m and y intercept b. The slope of parallel lines is the same, so in your case m is 2. To find b, substitute your given values for x and y with m=2.
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Principal Skinner
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