|
Welcome Guest | Login | |
|
Index
| Recent Threads
| Who's Online
| Register
| Search
| Help
| 
|
 |
WebGraphing.com Forum » List all forums » Forum: Tech Support General Forum » Thread: Help using calculator |
|
Total posts in this thread: 2 |
[Add To My Favorites] [Watch this Thread] [Post new Thread] |
| Author |
|
feyspirit
|
Hi, I just joined, and I am trying to imput a problem, but I apparently am not doing it correctly. The problem as it appears in my book is f(x)=2/3x^2-8/3x+5/3. I need to find the vertex, axis, domain and range, and then, graph it. I am supposed to be completing the square in order to find the vertex. I know that the calculator doesn't like the f(x). However, it seems like it wants me to give a "0" value on one side of the equal sign. I am not sure what I need to do. If you can help, I would really appreciate it. My thanks. Fey |
||
|
|
pskinner
Joined: Apr 2, 2005 Posts: 694 Status: Offline |
Two ways: If you use one of the graphing calculators, say: http://www.webgraphing.com/graphing_basic.jsp just enter the right side of the function, 2/3x^2-8/3x+5/3 If you use one of the "plotting" calculators, say: http://www.webgraphing.com/plotting_basic.jsp enter y=2/3x^2-8/3x+5/3. Finally, if you want to see how to "complete the square" take the right side and set it equal to 0 in: http://www.webgraphing.com/quadraticequation_completingthesquare.jsp ---------------------------------------- Principal Skinner |
||||
|
| [Show Thread Printable Version] [Post new Thread] |
Re: Help using calculator