|
Welcome Guest | Login | |
|
Index
| Recent Threads
| Who's Online
| Register
| Search
| Help
| 
|
 |
WebGraphing.com Forum » List all forums » Forum: Calculus Homework Help » Thread: Intercepts, Asymptotes, and Extremas... |
|
Total posts in this thread: 4 |
[Add To My Favorites] [Watch this Thread] [Post new Thread] |
| Author |
|
attalla19
|
Good Morning, I have these two problems that I need to do for homework. I am completely lost on how to do both. Can you please help? 1. Sketch y = (x/x^3)-x^2-3x+1 by finding the intercepts (if possible) and asymptotes (if any), and determine the extrema using the second derivative; also, find the point(s) of inflection. Label your sketch with the correct concavity. 2. Sketch y = (x-4)/(x^2+9) by finding the intercepts (if any), asymptotes (if any) and extrema (using the first derivative test). You are not required to find the point(s) of inflection. Fractions will be involved. Label your sketch. Note that a curve may pass through its horizontal asymptote. |
||
|
|
pskinner
Joined: Apr 2, 2005 Posts: 797 Status: Offline |
To get all the answers, just put each equation into the graphing calculator. Besides the graph, you get full tutorial solutions to all the problems you have. ---------------------------------------- Principal Skinner |
||
|
AdrianClark
 United States Joined: Apr 24, 2012 Posts: 1 Status: Offline |
Did you get solution? If you complete this sketch then share it. ---------------------------------------- tribulus terrestris |
||
|
|
dertson
United States Joined: Apr 27, 2012 Posts: 1 Status: Offline |
Here is an example.You can solve this in a similar way. x + 2 = 3x + -1x2 + 5 2 + x = 3x + -1x2 + 5 2 + x = 5 + 3x + -1x2 2 + x = 5 + 3x + -1x2 now solving for variable 'x'. 2 + -5 + x + -3x + x2 = 5 + 3x + -1x2 + -5 + -3x + x2 ---------------------------------------- google apps extensions |
||
|
| [Show Thread Printable Version] [Post new Thread] |
Re: Intercepts, Asymptotes, and Extremas...