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WebGraphing.com Forum » List all forums » Forum: General Discussions » Thread: Can you make sense of this simpification. |
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Total posts in this thread: 2 |
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I'm following my notes from class and can't figure out how this expression was simplified. / cos t (sin^4 t)dt = sin^5 t C thanks...pdt |
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Joined: Apr 2, 2005 Posts: 797 Status: Offline |
Not exactly sure what to make of C in: / cos t (sin^4 t)dt = sin^5 t C But if the problem is to integrate cos(t)*(sin(t))^4 as an indefinite integral, you can use a u-substitution, where u=sin(t) and du=cos(t)dt, so you can now integrate u^4*du and get (u^5)/5 +C. After substituting back, this becomes ((sin(t))^5)/5+C, which is "similar" to your notes (but fills in the details). ---------------------------------------- Principal Skinner |
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